Cs50 Tideman Solution -

if (cycle(winner, i))

char* tideman(Candidate candidates[], int num_candidates, Voter voters[], int num_voters) { // Count first-choice votes for (int i = 0; i < num_candidates; i++) candidates[i].votes = 0; Cs50 Tideman Solution

It looked something like this mentally:

return false;

This function checks if there is a path from loser to winner . i)) char* tideman(Candidate candidates[]

void record_preferences(int ranks[])

int margin = preferences[pairs[i].winner][pairs[i].loser] - preferences[pairs[i].loser][pairs[i].winner]; i++) candidates[i].votes = 0